WebApr 14, 2013 · var CarId = 23; //x.VehicleId property to match in the object array var carIndex = CarsList.map (function (x) { return x.VehicleId; }).indexOf (CarId); And for basic array numbers you can also do this: var numberList = [100,200,300,400,500]; var index = numberList.indexOf (200); // 1 You will get -1 if it cannot find a value in the array. Share WebYou can pass a selector to .index; it'll tell jQuery to search inside that for your element. var player = $ ('.player'), current = player.filter ('.currentPlayer'), index = current.index ('.player'); Or, you can tell jQuery to search for a specific element inside of an array:
JavaScript Array find() Method - GeeksforGeeks
WebJan 25, 2024 · To get position of the element of the array with JavaScript, we can use the array’s indexOf method. For instance, we write: const pos = [1, 2, 3, 4].indexOf (3); console.log (pos) to call indexOf on [1, 2, 3, 4] with 3 to get the index of 3 in the array. Therefore, pos is 2 since 3 is in the 3rd position in the array. Conclusion WebAug 25, 2012 · Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question.Provide details and share your research! But avoid …. Asking for help, clarification, or responding to other answers. history of headphones 1900
Return positions of a regex match () in Javascript?
WebDec 21, 2024 · Array indexes in JavaScript start at zero for the first item, so try this: var firstArrayItem = myValues [0] Of course, if you actually want the second item in the array at index 1, then it's myValues [1]. See Accessing array elements for more info. Share Improve this answer Follow edited Feb 15, 2024 at 1:40 Domagoj Vuković 153 2 8 WebFeb 19, 2010 · I had luck using this single-line solution based on matchAll ``` let regexp = /bar/g; let str = 'foobarfoobar'; let matchIndices = Array.from (str.matchAll (regexp)).map (x => x.index); console.log (matchIndices)``` – Steven Schkolne Jun 15, 2024 at 21:42 Add a comment 24 From developer.mozilla.org docs on the String .match () method: WebEven if this question is quite old, I would like to add a one-liner filter: Odd numbers: arr.filter((e,i)=>i%2) Even numbers: arr.filter((e,i)=>i%2-1) A more 'legal' way for even numbers: arr.filter((e,i)=>!(i%2)) There's no need to check with ===1 like sumit said.mod 2 already returns a 0 or a 1, you can let them be interpreted as boolean values.. You can … history of hazelden foundation